9/16/2023 0 Comments Template vector![]() Remember to compile with -std=c++11 to enable C++11. In this way, when the base class pointer's destructor is called, the derived class's destructor will be invoked. Each derived-class element can have different template types. Both shared_ptr and unique_ptr are supported by C++11 and Boost. The only way is to use the vector of shared_ptr or unique_ptr of a base class. ![]() Pushing the same class A of a different template type T will make each element in the vector have different sizes, thus, this is impossible. Its size will depend on the template variable "T obj". Therefore, suppose you define a template class A, template ![]() This makes addressing fast and convenient. In which each element must have the same size. The reason why this is NOT possible in C++, but possible in Java/Python is because: in a C++ vector, the STL container's storage (returned by vector::data()) contains all the object instantiations sequentially packed. ![]()
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